3.1.53 \(\int x^{10} (a^2+2 a b x^3+b^2 x^6)^{5/2} \, dx\)

Optimal. Leaf size=255 \[ \frac {b^5 x^{26} \sqrt {a^2+2 a b x^3+b^2 x^6}}{26 \left (a+b x^3\right )}+\frac {5 a b^4 x^{23} \sqrt {a^2+2 a b x^3+b^2 x^6}}{23 \left (a+b x^3\right )}+\frac {a^2 b^3 x^{20} \sqrt {a^2+2 a b x^3+b^2 x^6}}{2 \left (a+b x^3\right )}+\frac {a^5 x^{11} \sqrt {a^2+2 a b x^3+b^2 x^6}}{11 \left (a+b x^3\right )}+\frac {5 a^4 b x^{14} \sqrt {a^2+2 a b x^3+b^2 x^6}}{14 \left (a+b x^3\right )}+\frac {10 a^3 b^2 x^{17} \sqrt {a^2+2 a b x^3+b^2 x^6}}{17 \left (a+b x^3\right )} \]

________________________________________________________________________________________

Rubi [A]  time = 0.06, antiderivative size = 255, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {1355, 270} \begin {gather*} \frac {b^5 x^{26} \sqrt {a^2+2 a b x^3+b^2 x^6}}{26 \left (a+b x^3\right )}+\frac {5 a b^4 x^{23} \sqrt {a^2+2 a b x^3+b^2 x^6}}{23 \left (a+b x^3\right )}+\frac {a^2 b^3 x^{20} \sqrt {a^2+2 a b x^3+b^2 x^6}}{2 \left (a+b x^3\right )}+\frac {10 a^3 b^2 x^{17} \sqrt {a^2+2 a b x^3+b^2 x^6}}{17 \left (a+b x^3\right )}+\frac {5 a^4 b x^{14} \sqrt {a^2+2 a b x^3+b^2 x^6}}{14 \left (a+b x^3\right )}+\frac {a^5 x^{11} \sqrt {a^2+2 a b x^3+b^2 x^6}}{11 \left (a+b x^3\right )} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x^10*(a^2 + 2*a*b*x^3 + b^2*x^6)^(5/2),x]

[Out]

(a^5*x^11*Sqrt[a^2 + 2*a*b*x^3 + b^2*x^6])/(11*(a + b*x^3)) + (5*a^4*b*x^14*Sqrt[a^2 + 2*a*b*x^3 + b^2*x^6])/(
14*(a + b*x^3)) + (10*a^3*b^2*x^17*Sqrt[a^2 + 2*a*b*x^3 + b^2*x^6])/(17*(a + b*x^3)) + (a^2*b^3*x^20*Sqrt[a^2
+ 2*a*b*x^3 + b^2*x^6])/(2*(a + b*x^3)) + (5*a*b^4*x^23*Sqrt[a^2 + 2*a*b*x^3 + b^2*x^6])/(23*(a + b*x^3)) + (b
^5*x^26*Sqrt[a^2 + 2*a*b*x^3 + b^2*x^6])/(26*(a + b*x^3))

Rule 270

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.), x_Symbol] :> Int[ExpandIntegrand[(c*x)^m*(a + b*x^n)^p,
x], x] /; FreeQ[{a, b, c, m, n}, x] && IGtQ[p, 0]

Rule 1355

Int[((d_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_.) + (c_.)*(x_)^(n2_.))^(p_), x_Symbol] :> Dist[(a + b*x^n + c*x^
(2*n))^FracPart[p]/(c^IntPart[p]*(b/2 + c*x^n)^(2*FracPart[p])), Int[(d*x)^m*(b/2 + c*x^n)^(2*p), x], x] /; Fr
eeQ[{a, b, c, d, m, n, p}, x] && EqQ[n2, 2*n] && EqQ[b^2 - 4*a*c, 0] && IntegerQ[p - 1/2]

Rubi steps

\begin {align*} \int x^{10} \left (a^2+2 a b x^3+b^2 x^6\right )^{5/2} \, dx &=\frac {\sqrt {a^2+2 a b x^3+b^2 x^6} \int x^{10} \left (a b+b^2 x^3\right )^5 \, dx}{b^4 \left (a b+b^2 x^3\right )}\\ &=\frac {\sqrt {a^2+2 a b x^3+b^2 x^6} \int \left (a^5 b^5 x^{10}+5 a^4 b^6 x^{13}+10 a^3 b^7 x^{16}+10 a^2 b^8 x^{19}+5 a b^9 x^{22}+b^{10} x^{25}\right ) \, dx}{b^4 \left (a b+b^2 x^3\right )}\\ &=\frac {a^5 x^{11} \sqrt {a^2+2 a b x^3+b^2 x^6}}{11 \left (a+b x^3\right )}+\frac {5 a^4 b x^{14} \sqrt {a^2+2 a b x^3+b^2 x^6}}{14 \left (a+b x^3\right )}+\frac {10 a^3 b^2 x^{17} \sqrt {a^2+2 a b x^3+b^2 x^6}}{17 \left (a+b x^3\right )}+\frac {a^2 b^3 x^{20} \sqrt {a^2+2 a b x^3+b^2 x^6}}{2 \left (a+b x^3\right )}+\frac {5 a b^4 x^{23} \sqrt {a^2+2 a b x^3+b^2 x^6}}{23 \left (a+b x^3\right )}+\frac {b^5 x^{26} \sqrt {a^2+2 a b x^3+b^2 x^6}}{26 \left (a+b x^3\right )}\\ \end {align*}

________________________________________________________________________________________

Mathematica [A]  time = 0.02, size = 83, normalized size = 0.33 \begin {gather*} \frac {x^{11} \sqrt {\left (a+b x^3\right )^2} \left (71162 a^5+279565 a^4 b x^3+460460 a^3 b^2 x^6+391391 a^2 b^3 x^9+170170 a b^4 x^{12}+30107 b^5 x^{15}\right )}{782782 \left (a+b x^3\right )} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x^10*(a^2 + 2*a*b*x^3 + b^2*x^6)^(5/2),x]

[Out]

(x^11*Sqrt[(a + b*x^3)^2]*(71162*a^5 + 279565*a^4*b*x^3 + 460460*a^3*b^2*x^6 + 391391*a^2*b^3*x^9 + 170170*a*b
^4*x^12 + 30107*b^5*x^15))/(782782*(a + b*x^3))

________________________________________________________________________________________

IntegrateAlgebraic [A]  time = 19.23, size = 83, normalized size = 0.33 \begin {gather*} \frac {\sqrt {\left (a+b x^3\right )^2} \left (71162 a^5 x^{11}+279565 a^4 b x^{14}+460460 a^3 b^2 x^{17}+391391 a^2 b^3 x^{20}+170170 a b^4 x^{23}+30107 b^5 x^{26}\right )}{782782 \left (a+b x^3\right )} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[x^10*(a^2 + 2*a*b*x^3 + b^2*x^6)^(5/2),x]

[Out]

(Sqrt[(a + b*x^3)^2]*(71162*a^5*x^11 + 279565*a^4*b*x^14 + 460460*a^3*b^2*x^17 + 391391*a^2*b^3*x^20 + 170170*
a*b^4*x^23 + 30107*b^5*x^26))/(782782*(a + b*x^3))

________________________________________________________________________________________

fricas [A]  time = 1.56, size = 57, normalized size = 0.22 \begin {gather*} \frac {1}{26} \, b^{5} x^{26} + \frac {5}{23} \, a b^{4} x^{23} + \frac {1}{2} \, a^{2} b^{3} x^{20} + \frac {10}{17} \, a^{3} b^{2} x^{17} + \frac {5}{14} \, a^{4} b x^{14} + \frac {1}{11} \, a^{5} x^{11} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^10*(b^2*x^6+2*a*b*x^3+a^2)^(5/2),x, algorithm="fricas")

[Out]

1/26*b^5*x^26 + 5/23*a*b^4*x^23 + 1/2*a^2*b^3*x^20 + 10/17*a^3*b^2*x^17 + 5/14*a^4*b*x^14 + 1/11*a^5*x^11

________________________________________________________________________________________

giac [A]  time = 0.44, size = 105, normalized size = 0.41 \begin {gather*} \frac {1}{26} \, b^{5} x^{26} \mathrm {sgn}\left (b x^{3} + a\right ) + \frac {5}{23} \, a b^{4} x^{23} \mathrm {sgn}\left (b x^{3} + a\right ) + \frac {1}{2} \, a^{2} b^{3} x^{20} \mathrm {sgn}\left (b x^{3} + a\right ) + \frac {10}{17} \, a^{3} b^{2} x^{17} \mathrm {sgn}\left (b x^{3} + a\right ) + \frac {5}{14} \, a^{4} b x^{14} \mathrm {sgn}\left (b x^{3} + a\right ) + \frac {1}{11} \, a^{5} x^{11} \mathrm {sgn}\left (b x^{3} + a\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^10*(b^2*x^6+2*a*b*x^3+a^2)^(5/2),x, algorithm="giac")

[Out]

1/26*b^5*x^26*sgn(b*x^3 + a) + 5/23*a*b^4*x^23*sgn(b*x^3 + a) + 1/2*a^2*b^3*x^20*sgn(b*x^3 + a) + 10/17*a^3*b^
2*x^17*sgn(b*x^3 + a) + 5/14*a^4*b*x^14*sgn(b*x^3 + a) + 1/11*a^5*x^11*sgn(b*x^3 + a)

________________________________________________________________________________________

maple [A]  time = 0.01, size = 80, normalized size = 0.31 \begin {gather*} \frac {\left (30107 b^{5} x^{15}+170170 a \,b^{4} x^{12}+391391 a^{2} b^{3} x^{9}+460460 a^{3} b^{2} x^{6}+279565 a^{4} b \,x^{3}+71162 a^{5}\right ) \left (\left (b \,x^{3}+a \right )^{2}\right )^{\frac {5}{2}} x^{11}}{782782 \left (b \,x^{3}+a \right )^{5}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^10*(b^2*x^6+2*a*b*x^3+a^2)^(5/2),x)

[Out]

1/782782*x^11*(30107*b^5*x^15+170170*a*b^4*x^12+391391*a^2*b^3*x^9+460460*a^3*b^2*x^6+279565*a^4*b*x^3+71162*a
^5)*((b*x^3+a)^2)^(5/2)/(b*x^3+a)^5

________________________________________________________________________________________

maxima [A]  time = 0.81, size = 57, normalized size = 0.22 \begin {gather*} \frac {1}{26} \, b^{5} x^{26} + \frac {5}{23} \, a b^{4} x^{23} + \frac {1}{2} \, a^{2} b^{3} x^{20} + \frac {10}{17} \, a^{3} b^{2} x^{17} + \frac {5}{14} \, a^{4} b x^{14} + \frac {1}{11} \, a^{5} x^{11} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^10*(b^2*x^6+2*a*b*x^3+a^2)^(5/2),x, algorithm="maxima")

[Out]

1/26*b^5*x^26 + 5/23*a*b^4*x^23 + 1/2*a^2*b^3*x^20 + 10/17*a^3*b^2*x^17 + 5/14*a^4*b*x^14 + 1/11*a^5*x^11

________________________________________________________________________________________

mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int x^{10}\,{\left (a^2+2\,a\,b\,x^3+b^2\,x^6\right )}^{5/2} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^10*(a^2 + b^2*x^6 + 2*a*b*x^3)^(5/2),x)

[Out]

int(x^10*(a^2 + b^2*x^6 + 2*a*b*x^3)^(5/2), x)

________________________________________________________________________________________

sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int x^{10} \left (\left (a + b x^{3}\right )^{2}\right )^{\frac {5}{2}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**10*(b**2*x**6+2*a*b*x**3+a**2)**(5/2),x)

[Out]

Integral(x**10*((a + b*x**3)**2)**(5/2), x)

________________________________________________________________________________________